Torque conversion
1 newton-centimeter (N·cm) equals 0.007375621493 pound-foot (lbf·ft). Enter any value below to convert from N·cm to lbf·ft.
Enter a value and choose units. Results update instantly.
1 N·cm = 0.0073756215 lbf·ft
| Unit | Value |
|---|---|
| Newton-meter N·m | 0.01 |
| Kilonewton-meter kN·m | 0.00001 |
| Newton-centimeter N·cm | 1 |
| Pound-foot lbf·ft | 0.0073756215 |
| Pound-inch lbf·in | 0.0885074579 |
| Kilogram-force meter kgf·m | 0.0010197162 |
| Ounce-force inch ozf·in | 1.4161193266 |
Formula
Use this relationship for a direct conversion:
2 N·cm = 0.014751243 lbf·ft.
Factors use exact international length definitions and conventional standard gravity for force-based units.
Quick reference
| Newton-centimeter (N·cm) | Pound-foot (lbf·ft) |
|---|---|
| 0.01 | 0.0000737562 |
| 0.1 | 0.0007375621 |
| 1 | 0.0073756215 |
| 2 | 0.014751243 |
| 5 | 0.0368781075 |
| 10 | 0.0737562149 |
| 25 | 0.1843905373 |
| 50 | 0.3687810746 |
| 100 | 0.7375621493 |
| 1,000 | 7.3756214928 |
From unit
One newton acting at one centimeter.
Symbol: N·cm
To unit
One pound-force acting at one foot.
Symbol: lbf·ft
Keep converting
Source
Definitions are checked against NIST SP 811: Torque and moment of force. Calculations use full internal precision before display rounding.
View the complete torque converterQuestions
Use the formula lbf·ft = N·cm x 0.007375621493. 1 newton-centimeter (N·cm) equals 0.007375621493 pound-foot (lbf·ft).
Factors use exact international length definitions and conventional standard gravity for force-based units.
